4cos^2x+4sin-1=0

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Solution for 4cos^2x+4sin-1=0 equation:


Simplifying
4cos2x + 4sin + -1 = 0

Reorder the terms:
-1 + 4cos2x + 4ins = 0

Solving
-1 + 4cos2x + 4ins = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 4cos2x + 1 + 4ins = 0 + 1

Reorder the terms:
-1 + 1 + 4cos2x + 4ins = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4cos2x + 4ins = 0 + 1
4cos2x + 4ins = 0 + 1

Combine like terms: 0 + 1 = 1
4cos2x + 4ins = 1

Add '-4ins' to each side of the equation.
4cos2x + 4ins + -4ins = 1 + -4ins

Combine like terms: 4ins + -4ins = 0
4cos2x + 0 = 1 + -4ins
4cos2x = 1 + -4ins

Divide each side by '4os2x'.
c = 0.25o-1s-2x-1 + -1ino-1s-1x-1

Simplifying
c = 0.25o-1s-2x-1 + -1ino-1s-1x-1

Reorder the terms:
c = -1ino-1s-1x-1 + 0.25o-1s-2x-1

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